(cos^2)x=(1/2)sin2x

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Solution for (cos^2)x=(1/2)sin2x equation: 


Oblicz to!

(-1/8)*(-1/9)*x*x^8 = 0

((((-3/14)*x^2)/12)/49)*x^3 = 0

(5*t^4-1)^4

y = 2*x^2-8*x+4;2;-8;4

-(((-8)^2-(2*4*4))/(2*4))

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